1/3b=(b+5/6b^2)-(5/2b^2)

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Solution for 1/3b=(b+5/6b^2)-(5/2b^2) equation: 


b in (-oo:+oo)

(1/3)*b = (5/6)*b^2-((5/2)*b^2)+b // - (5/6)*b^2-((5/2)*b^2)+b

(5/2)*b^2-((5/6)*b^2)+(1/3)*b-b = 0

(-5/6)*b^2+(5/2)*b^2+(1/3)*b-b = 0

5/3*b^2-2/3*b = 0

DELTA = (-2/3)^2-(0*5/3*4)

DELTA = 4/9

DELTA > 0

b = ((4/9)^(1/2)+2/3)/(5/3*2) or b = (2/3-(4/9)^(1/2))/(5/3*2)

b = 2/5 or b = 0

b in { 0, 2/5 }

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